Thursday, 21 April 2016

Capacity Building Key to Achieving 10,000mw By 2019 – Fashola



The ministerof power, works and housing, Babatunde Fashola, has stated that the target of 10,000 megawatts (mw) by 2019 will not be realised except skilled manpower needs are addressed in the sector.

Fashola, who emphasised that design, building of plant, its operation and maintenance, can only be carried out by key skilled manpower, underscored the role of the National Power Training Institute of Nigeria (NAPTIN), in the realisation of the 10,000mw target.

Speaking during a ceremony for graduating trainees under the NAPTINS Graduate Skills Development Programme (NGSDP), the minister urged the trainees to brace up to this challenge by developing positive attitude that would enable them to be creative in solving the myriad of problems responsible for the lack of access to power by many Nigerians.

Represented by the permanent secretary, Power, Mr Louis Edozien, Fashola said that there will soon be executive actions on issues around renewable energy, coal, embedded generation and the need for a workable training policy for the NAPTIN.

He also informed that the governmentwas looking at the quest for making the NAPTIN a citadel of quality learning with its proposed post-graduate degree programmes.

Speaking earlier, the director-general of the NAPTIN, Mr Reuben Okeke, had requested the minister to help fast-track the plan to incorporate the training of lower cadre personnels, similar to the now rested National Power Apprenticeship Scheme (NAPSAS) in the sector, to complement the trained engineers that are primarily the focus of the institute.
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Stop Crucifying Toyin Aimakhu, We All Make Mistakes – Mercy Aigbe

Following popular Yoruba actress,Toyin Aimakhu’slatest saga with ex-lover,Seun Egbegbe and social media criticism,Mercy Aigbe has come to her defence.

The lovely actress today,Thursday,April 21, 2016 took to Instagramto share a photo of Aimakhu asking the actress to stay strong.

According to her, the ‘Alakada‘ actress can always count on her in this disturbing and trying times.

She wrote, “Today I am crushing on my talented, beautiful Edo, down to earth, crazy and fun to be with @aimakhutoyin I love You aburo, continue to stay strong, you know you can always count on me (thats if u will listen oh ) "Pls all those who are crucifying my sis, biko leave her alone oh! We all make mistakes and we learn from it……love you sweets.“
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Wednesday, 20 April 2016

Waec 2016/2017 May/June Mathematics Paper 1 & 2 Essay,obj, theory Question and answer

MATHS OBJ: 1-10: DCBCABBADA 11-20: CCBDABABBA

21-30: CACCDDDACC

31-40: BCDCDCBADA

41-50: ABACBBDADD

(1a) (0.09*1.21)/(3.3*0.00025) =(9*10^-2*1.2*10^1)/(3.3*25*10^-5) =(1089^10^-4)/(82.5*10^-5) =1.32*10^(-4+6) =1.32*10^2 (1b) p=5600,T=3,A=1200+5600=6800 A=P(1+R/100)^3 6800=5600(1+R/100)^3 (1+R/100)^3=6800/5600 (1+R/100)^3=1.214 1+R/100=cuberoot(1.214) 1+R/100=1.0667 R/100=1.0667-1 R/100=0.0667 R=0.0667*100 R=66.7% (2a) 7(x+4)-2/3(x-6)<_2[x-3(x+5)] 7x+28-2x/3-4<_2[x-3x-15] 24+7x-2x/3<_2x-6x-30 7x-2x/3-2x+6x<_-30-24 11x-2x/3<_-54 33x-2x<_-162 31x<_-162 x<_-162/31 (2b) x = tricycles and y = taxi cabs 2x+4y=6b … (1) x+y=20 … (2) from equ..(2) y=20-x substitute for y in equ…(1) 2x+4(20-x) = 66 2x+80-4x=66 80-66=4x-2x 14/2 = 2x/2 x=7 number of tricycles = 7 3b) h=7cm T=462cm^2 T=pie sqr + 2 pie rH 462= pie( r ^2 +2*7*r) 462/3.142 =r sqr= =14r r sqr+ 14r=147 r sqr +14r- 147=0 r= 14+-( (sqr(14))-4*1*147)/2*1 r=-(14 +-(196-4))/2 r=(-14+_12)/2 r=(-14+12)/2 or r=2/2 =1cm ================================== (4a) Pr(3)=x/total total=25+30+x+28+40+32 =155+x 0.225=x/155+ x =34.875+0.225x=x x-0.225x=34.875 =0.775x=34.875 degree x=34.875/0.775 =45 ================================== (4b) Pr(even)=30+28+40+32 =90 Pr(even)=90/200=9/20 Pr(prime no)=25=30+45+40 =140 Pr(prime no)=140/200=14/20 Pr(even or prime)=9/20 + 14/20 =========================== (5a) Area PSR=1/2*PR*SM PR=8+6=14cm 36=1/2 * 14* 6 36=1/2 * 14* 6 *QR QR=8.6cm ================================== (5b) diagram sin45 degree= 10.65/h h=10.65/sin 45 degree =10.65/0.7071 h=15.06cm =============================== (6a) first term9a)=1.0=1 common diff(d)=3-1=2 last term(L)=101 L=a+(n-1)d 101=1+(n-1)*2 (n-1)*2=100 n-1=100/2 n-1=50 n=501+1 n=51 sum(s)=n/2(2a+(n-1)d) S=51/2(2*1+(51-1)*2) s=25.5(2+100) S=25.5*102=2601 ================================== (6b) UC=95 Bus & Train(B&T)=7 Train & Car( T & C)=3 B&T&C=8 Bus only(x)=B&C only Bus(b)=47 train(T)=30 (draw the venn diagram) Bus only= 47-(7+8+x) x=47-15+x 47=x+x+7+8 47=2x+15 2x=47-15 2x=32 x=32/2 =16 Train only= 30-(7+8+2) =30-18=12 ==================== (6bi)=x=16 ==================== (6bii) number who travelled by at leasttwo means =7+1+3+8 =19 ================================== (7a) given; (x-2)/4=(x+2)/2x 2x*(x-2)=4*(x+2) 2x^2 -4x= 4x+8 2x^2-4x-4x-8=0 2x^2-8x-8=0 x^2-4x-4=0 x^2-4x=4 x^2-(4* 1/2)=4+(2)^2 (x-2)^2=4+4 (x-2)^2=8 (x-2)= sqr root(8) x-2=+-2.83 x=+-2.83 x=+_2.83+2 x=-2.83+2 x=4.83 or x=-0.83 ========================== (7b) P+Q+S=180 degree(sum of angles in a triangle) 52 degree+ 90 degree+ S= 180 degree 142+ S=180 S=180-142 S=38 degree ============================= (i)52+38+SQT =180 degree SQT=180-90 SQT=90 degree (ii)PQT= 52 degree ============================== (8a) diagram z=110 degree(sum of angles on a straight line) z=180-110 z=70 dgree w degree= 70 degree x+r+w degree= 180 degree(sum of angle in a triangle) x+2x+70 degree=180 degree 3x=110 x=110/3=36.7 dgeree ================================== (8b) B=10, G=12 TB=600.00 TB=TG+600 mean of TB=100+ mean of TG where TB= total collection of boys TG=total collection by girls mean of TB= ET/B mean of TB= (TG+600)/10 100+ mean of TG= (TG+600)/100 mean of TG= mean of TG/12 100+ mean of G/12= (TG+600)/10 (100+TG)/12=(TG+600)/10 10*(1200+TG)=12*(TG+600) =12000+10TG=12TG+7200 =12TG-10TG=12000-7200 2TG=4800 TG=N2400 TB=TG+600 TB=600+2400 Tb=N3000 ============================= (11a) Given (3p+4q)/(3p-4q) = 2 3p+4q=2*(3p-4q) 3p+4q=6p-8q 3p-6p=-4q-8q =-3p=-12q p/q=-12/-3 p/q=4/1, P=4, q=1 p:q=4;1 ================================== (11b) (i) perimeter(p)=PQ+PU+QR PQ=UT+TS+SR 34=PQ+UR+4+4 PQ=UR 34-8=2PQ PQ=26/2=13cm ================================== (ii) 13=2+TS+2 TS=13-4=9cm radius(r)=9/2=4.5cm Area(A)= pie r sqr+22/7*(4.5)^2 =445.5/7 63.64cm^2
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Music: Olamide X Kenny G below - Who You Epp



Another Fast rising indigeous rapper is very talented after successful "Below" Single and bounce on who you epp competition "Kenny G below" jump on Olamide Ybnl Boss Who you help? Freestyle

#Who You Epp Competition initiated by Olamide Baddo. Enjoy!!

Download



Download 2

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WAEC 2016 May/June 100% Correct Agricultural Pratical Paper, Question And Answers

(1a) Experiment to compare the porosity and water holding capacity

(1b) Grind loam and clay soil into fine particles, after drying in the sun. Equal masses of the dry, dry clay and dry loam are place seperately into three funnels which are blocked at the neck with cotton wool. The three funnels containing different types of soil are then placed on top of the three measuring cylinders. Then quickly pour equal amount of water into the funnels, containing each soil type. Then leave for an hour

(1c) (i)Loamy (ii)Sandy (iii)Clay

(1d) (i) I will ensure the three funnels containing different types of soil are placed on top of the three measuring cylinders (ii) I will ensure equal amount of water is quickly poured into the funnels containing the soil type (1e) -Sandy soil: Because the porosity is high in sandy soil because of large pores spaces and larger particles sizes ===================================

(2a) Ranging pole is a surveying instrument consisting of a straight rod pointed in bands of alternate red and white each one foot wide,used for sighting by surveyors

(2b) A-For making positions in surveying -For sighting by surveyor B-For marking posititon on surveying land C-For measuring the lenght of land -For detecting area of land (2c) A-By cleaning after use -By keeping in cool dry place B-By keeping away from water -By not exposing it to direct sunlight for so long C-By cleaning after use -By keeping in a cool dry place ======================================= (3ai) G-Herbivore H-Herbivore (3aii) G-Leaves(Defilators) H-Fruits

(3aiii) H-It helps in pollination -They help in dispersal of fruit -They help in the dispersal of seeds

(3aiv) I-It can be controlled using scar scrow J-It can be controlled using traps.It can also be controlled using biological method eg use of cat ===================================== (4a) N: -Animal feed industry -ceramic Industry -pharmaceutical industry O: -paint industries -pharmaceutical industries -cosmetic industries

(4b) -it causes loss of weight -it causes loss of appetite -it causes anaemia -it damages some internal organs -it prevent respiration

(4c) -by dipping the animal -by drenching -by clearing bushes around -by giving the animal injection
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Tuesday, 19 April 2016

Unijos Remedial Admission List 2015/2016 Available On The School Portal

This is to inform candidates who applied for the 2015/2016 remedial Programme of the University of Jos that they can now check their admission status on the school website.

To check your admission status, visit CLICK HERE-Enter your JAMB Reg Number, Full name in the spaces provided.

-Select the academic session -Click on “Find Details” to access your status
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OAU Notice to Admitted Candidates on 2015/2016 Acceptance Fee Payment

This is to inform 2015/2016 admitted candidates of Obafemi Awolowo University, Ile-Ife that they are to;

1. Accept their various admissions by paying thier acceptance fee of #20,000 before interacting with their pages on the E-portal.

2.The facility to download RRR for acceptance fee payment on CLICK HEREwould be ready by Wednesday, 20th of April 2016.

3. Download the RRR on the E-portal only ( CLICK HERE)

4. Visit banks that accept payment into REMITAL to make your payment there after return to CLICK HERE click on “undergraduate login”. Enter your JAMB Registration number as the username and your surname as the password to continue with your registration
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Designed by Jide Ogunsanya.